JAMB - Mathematics (1983 - No. 42)
30o 35'
30o 32'
15o 36'
10o
10o 42'
ব্যাখ্যা
tan\(\theta\) = \(\frac{0.8}{2}\) = (0.4)
\(\theta\) = tan-1(0.4)
From the diagram, the inclination of the diagonal PR to the horizontal is 10o 42'
\(\theta\) = tan-1(0.4)
From the diagram, the inclination of the diagonal PR to the horizontal is 10o 42'