JAMB - Mathematics (1982 - No. 8)
Write the equation 2 log2x - x log2(1 + y) = 3 in a form not involving logarithms
2x(1 + y) = 3
2x - x(1 + y) = 8
x2 = 8(1 + y)x
x2 - x(1 + y) = 8
x2 - (1 + y)2 = 8
ব্যাখ্যা
2log2 x - x log2 (1 + y) = 3
log2 \(\frac{x^2}{(1 + y)^x}\) = 3
= \(\frac{x^2}{(1 + y)^x}\)
= 23
= 8
= x2 = 8(1 + y)x
log2 \(\frac{x^2}{(1 + y)^x}\) = 3
= \(\frac{x^2}{(1 + y)^x}\)
= 23
= 8
= x2 = 8(1 + y)x