JAMB - Mathematics (1978 - No. 25)

A triangle has angles 30o, 15o and 135o. The side opposite to the angle 30o is length 6cm. The side opposite to the angle 135o is equal to

12cm

6cm

6\(\sqrt{2}\)cm

12\(\sqrt{2}\)cm

\(\frac{6}{\sin 30}\) = \(\frac{x}{\sin 135}\)

\(\frac{6}{\sin 30}\) = \(\frac{x}{\sin 45}\)

x = \(\frac{6 \times \sin 45}{\sin 30}\)

= \(6 \sqrt{2}\)cm