WAEC - Physics (1990 - No. 47)
A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series with an ammeter of resistance 0.59 and a resistor of resistance 7.09. Calculate the current in the circuit.
0.15 A
0.20 A
0.60A
3.00A
6.67 A.
Обяснение
I =
ER + r
= 1.52.5 + 0.5 + 7
= 0.15