WAEC - Mathematics (2015 - No. 19)
In the diagram, O is the centre, \(\bar{RT}\) is a diameter, < PQT = 33\(^o\) and < TOS = 76\(^o\). Using the diagram, find the size of angle PRS.
76o
71o
38o
33o
Обяснение
In the diagram, < TRS = \(\frac{76^o}{2}\) = 38\(^o\)
Hence, angle PRS = 33\(^o\) + 38\(^o\)
= 71\(^o\)
Hence, angle PRS = 33\(^o\) + 38\(^o\)
= 71\(^o\)