ExamPlay Light Logo
Вход

JEE Advance - Mathematics (1994 - No. 43)

In a triangle $$ABC$$, $$AD$$ is the altitude from $$A$$. Given $$b>c$$, $$\angle C = {23^ \circ }$$ and $$AD = {{abc} \over {{b^2} - {c^2}}}$$ then $$\angle B = $$.................
23°
67°
113°
46°
90°

Коментари (0)

Влезте, за да коментирате
Реклама
BrainBehindX Inc Logo
©2026; Осъществено от BrainBehindX Inc