JAMB - Physics (2013 - No. 8)
An object is moving with a velocity of 5m-1. At what height must a similar body be situated to have a potential energy equal in value with kinetic energy of the moving body?
25.0m
20.0m
1.3m
1.0m
Обяснение
P.E = K.E
Therefore, h = \(\frac{v^2}{2g} = \frac{5^2}{2 \times 10}\)
= 1.25
Approx 1.3 (C)
Therefore, h = \(\frac{v^2}{2g} = \frac{5^2}{2 \times 10}\)
= 1.25
Approx 1.3 (C)