JAMB - Mathematics (2009 - No. 14)
Determine the value of x for which (x\(^2\) - 1) > 0?
x < -1 or x > 1
-1 < x < 1
x > 0
x < -1
Обяснение
x\(^2\) > 0
(x+1)(x-1) > 0
x = 1 or -1
x < -1 or x > 1
x\(^2\) > 0
(x+1)(x-1) > 0
x = 1 or -1
x < -1 or x > 1