WAEC - Mathematics (2023 - No. 2)
Solve \(1 + \sqrt[3]{ x - 3} = 4\)
30
6
12
66
توضيح
\(1 + \sqrt [3]{x-3} = 4\)
= \(\sqrt[3]{x - 3} = 4 - 1\)
\(\sqrt[3]{x - 3} = 3 \)
take the cube of both sides
= x - 3 = 27
x = 27 + 3
∴ x = 30
\(1 + \sqrt [3]{x-3} = 4\)
= \(\sqrt[3]{x - 3} = 4 - 1\)
\(\sqrt[3]{x - 3} = 3 \)
take the cube of both sides
= x - 3 = 27
x = 27 + 3
∴ x = 30