WAEC - Mathematics (2019 - No. 26)
Make b the subject of the relation lb = \(\frac{1}{2}\) (a + b)h
\(\frac{ah}{2l - h}\)
\(\frac{2l - h}{al}\)
\(\frac{al}{2l - h}\)
\(\frac{al}{2 - h}\)
توضيح
lb = \(\frac{1}{2} (a + b)h
2lb = ah + bh
2lb - bh = ah
\(\frac{b(2l - h)}{2l - h} = \frac{ah}{2l - h}\)
b = \(\frac{ah}{2l - h}\)