JEE Advance - Mathematics (1983 - No. 38)
Show that $$1+x$$ $$In\left( {x + \sqrt {{x^2} + 1} } \right) \ge \sqrt {1 + {x^2}} $$ for all $$x \ge 0$$
The inequality is false for x = 0.
The inequality is true for all x ≥ 0.
We cannot determine if the inequality is true or false without further analysis.
The inequality is only true for specific values of x.
The inequality can be solved directly for x.